Hola,
prueba a poner esto....
echo date('d - m - y',odbc_result($queryC,1));
Comprueba que $queryC,1 sea el campo fecha...
... si sigue sin salirte aquí te pongo un poco de información sobre el formateo de fechas en mysql...
Funcion DATE_FORMAT de MYsql es...
DATE_FORMAT(date,format)
Formats the date value according to the format string. The following
specifiers may be used in the format string:
%M Month name (January..December)
%W Weekday name (Sunday..Saturday)
%D Day of the month with English suffix (1st, 2nd, 3rd, etc.)
%Y Year, numeric, 4 digits
%y Year, numeric, 2 digits
%X Year for the week where Sunday is the first day of the week, numeric,
4 digits, used with '%V'
%x Year for the week, where Monday is the first day of the week, numeric,
4 digits, used with '%v'
%a Abbreviated weekday name (Sun..Sat)
%d Day of the month, numeric (00..31)
%e Day of the month, numeric (0..31)
%m Month, numeric (01..12)
%c Month, numeric (1..12)
%b Abbreviated month name (Jan..Dec)
%j Day of year (001..366)
%H Hour (00..23)
%k Hour (0..23)
%h Hour (01..12)
%I Hour (01..12)
%l Hour (1..12)
%i Minutes, numeric (00..59)
%r Time, 12-hour (hh:mm:ss [AP]M)
%T Time, 24-hour (hh:mm:ss)
%S Seconds (00..59)
%s Seconds (00..59)
%p AM or PM
%w Day of the week (0=Sunday..6=Saturday)
%U Week (0..53), where Sunday is the first day of the week
%u Week (0..53), where Monday is the first day of the week
%V Week (1..53), where Sunday is the first day of the week. Used with
'%X'
%v Week (1..53), where Monday is the first day of the week. Used with
'%x'
%% A literal `%'.
Ejemplo....
SELECT date_format(lastaccesstime, '%M %e, %Y') FROM user WHERE userid =
'hecky';
.
Un saludo, esperando ser de ayuda...
COMUN
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