Mostrar nota si campo = vacio

[T4ke0veR]

hice esto

Código PHP:

    <?php if( count( $row_Recordset1 ) > 0 ) { ?> 
 
                                        </span><br /> 
                                    </p> 
                                    <table width="80%" border="0" align="center" cellpadding="0" cellspacing="4"> 
                              <tr> 
                                <td width="69%"><div align="left" class="textoTitulos"><strong><?php echo $row_Recordset1['empresa']; ?></strong></div></td> 
                                <td width="31%">R.I.F.: <?php echo $row_Recordset1['rif']; ?></td> 
                              </tr> 
                              <tr> 
                                <td><div align="left">Gerente de tienda: <?php echo $row_Recordset1['operador']; ?></div></td> 
                                <td>&nbsp;</td> 
                              </tr> 
                              <tr> 
                                <td colspan="2"><div align="left">Direcci&oacute;n: <?php echo $row_Recordset1['direccion']; ?></div></td> 
                                </tr> 
                              <tr> 
                                <td colspan="2"><div align="left">Tel&eacute;fonos: <?php echo $row_Recordset1['telefono']; ?></div><?php } ?><?php else { 
      {echo "No existen tiendas en esta region";} 
}  ?>   

y me dice esto
Parse error: syntax error, unexpected T_ELSE in C:\wamp\www\Tienda del pintor\site\detalle_mapa.php on line 222

linea 222 en adelante

Código PHP:

                                <td colspan="2"><div align="left">Tel&eacute;fonos: <?php echo $row_Recordset1['telefono']; ?></div><?php } ?><?php else { 
      {echo "No existen tiendas en esta region";} 
}  ?>