Este es el codigo completo del CryptPassword.pl:
#!/usr/bin/perl -w
# --
# bin/CryptPassword.pl - to crypt database password for Kernel/Config.pm
# Copyright (C) 2001-2004 Martin Edenhofer <
[email protected]>
# --
# $Id: CryptPassword.pl,v 1.1 2004/06/22 08:01:28 martin Exp $
# --
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
# --
use strict;
use vars qw($VERSION);
$VERSION = '$Revision: 1.1 $';
$VERSION =~ s/^\$.*:\W(.*)\W.+?$/$1/;
# --
# check args
# --
my $Password = shift;
print "bin/CryptPassword.pl <Revision $VERSION> - to crypt database password for Kernel/Config.pm\n";
print "Copyright (c) 2001-2004 Martin Edenhofer <martin\@otrs.org>\n";
if (!$Password) {
print STDERR "Usage: bin/CryptPassword.pl NEWPW\n";
}
else {
my $Length = length($Password)*8;
chomp $Password;
# get bit code
my $T = unpack("B$Length", $Password);
# crypt bit code
$T =~ s/1/A/g;
$T =~ s/0/1/g;
$T =~ s/A/0/g;
# get ascii code
$T = pack("B$Length", $T);
# get hex code
my $H = unpack("h$Length", $T);
print "Crypted password: {$H}\n";
}
Yo creo que es lo mismo que te puse. El problema es que el programa que intento integrar en mi aplicacion y que esta hecho en PERL en la base de datos mete prjqSmRFQBP7c. Y no se como hace para sacar ese resultado.
gracias