Hola amigos tengo esta tabla:
Código PHP:
-- Estructura de tabla para la tabla `comercio`
--
CREATE TABLE `comercio` (
`id_comercio` int(50) NOT NULL auto_increment,
`razon_social` varchar(100) NOT NULL,
`responsable` varchar(100) NOT NULL,
`direccion` varchar(100) NOT NULL,
`cuit` varchar(100) NOT NULL,
`telefono` varchar(100) NOT NULL,
`celular` varchar(100) NOT NULL,
`ciudad` varchar(100) NOT NULL,
`mail` varchar(100) NOT NULL,
`cod_postal` varchar(100) NOT NULL,
`observaciones` varchar(100) NOT NULL,
`usuario` varchar(100) NOT NULL,
`password` varchar(100) NOT NULL,
`accion` int(9) unsigned NOT NULL default '0',
PRIMARY KEY (`id_comercio`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ;
y tengo este otro php que es el que identifica al usuario y lo redirecciona.
Código PHP:
<?php
//Start session
session_start();
//Include database connection details
require_once('config.php');
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Connect to mysql server
/*$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link) {
die('Failed to connect to server: ' . mysql_error());
}
//Select database
$db = mysql_select_db(DB_DATABASE);
if(!$db) {
die("Unable to select database");
} */
//Function to sanitize values received from the form. Prevents SQL injection
function clean($str) {
$str = @trim($str);
if(get_magic_quotes_gpc()) {
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
//Sanitize the POST values
$login = clean($_POST['login']);
$password = clean($_POST['password']);
//Input Validations
if($login == '') {
$errmsg_arr[] = 'Login ID missing';
$errflag = true;
}
if($password == '') {
$errmsg_arr[] = 'Password missing';
$errflag = true;
}
//If there are input validations, redirect back to the login form
if($errflag) {
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
session_write_close();
header("location: login-form.php");
exit();
}
//Create query
//$qry="SELECT * FROM comercio WHERE usuario='$login' AND password='".md5($_POST['password'])."'";
$qry="SELECT * FROM comercio WHERE usuario='$login' AND password='$password'";
$result=mysql_query($qry);
//Create query
//$qry="UPDATE comercio SET id_comercio='id_comercio' AND accion='$accion' + 1";
$qry="UPDATE comercio SET id_comercio = id_comercio +1 WHERE accion =1'";
$result=mysql_query($qry);
//Check whether the query was successful or not
if($result) {
if(mysql_num_rows($result) == 1) {
//Login Successful
session_regenerate_id();
$member = mysql_fetch_assoc($result);
$_SESSION['SESS_MEMBER_ID'] = $member['id_comercio'];
$_SESSION['SESS_FIRST_NAME'] = $member['razon_social'];
//$_SESSION['SESS_LAST_NAME'] = $member['lastname'];
session_write_close();
header("location: member-index.php");
exit();
}else {
//Login failed
header("location: login-failed.php");
exit();
}
}else {
die("Query failed");
}
?>
El tema que quiero es poder cuando un comercio se loguea, me aumente la cantidad de login de 1 en 1 en el campo ACCION de la Tabla COMERCIO.
Tengo esta query pero no me esta funcionando:
Código PHP:
//Create query
//$qry="UPDATE comercio SET id_comercio='id_comercio' AND accion='$accion' + 1";
$qry="UPDATE comercio SET id_comercio = id_comercio +1 WHERE accion =1'";
$result=mysql_query($qry);
Alguien podria explicarme en donde tengo el error que no me suma dependiendo el comercio que se loguea en el campo accion.
Saludos y gracias