hola amigos estoy usuado un plugin de jquery llamado jraiting mi pregunta es como puedo hacer para conectarme a mi bd mysql que tablas tengo que crear ???, creo que es por este archivo pero no lo entiendo muy bien...
Código PHP:
<?php
$aResponse['error'] = false;
$aResponse['message'] = 'No se ha conectado al servidor';
// ONLY FOR THE DEMO, YOU CAN REMOVE THIS VAR
$aResponse['server'] = '';
// END ONLY FOR DEMO
if(isset($_POST['action']))
{
if(htmlentities($_POST['action'], ENT_QUOTES, 'UTF-8') == 'rating')
{
/*
* vars
*/
$id = intval($_POST['idBox']);
$rate = floatval($_POST['rate']);
// YOUR MYSQL REQUEST HERE or other thing :)
/*
*
*/
// if request successful
$success = true;
// else $success = false;
// json datas send to the js file
if($success)
{
$aResponse['message'] = 'Your rate has been successfuly recorded. Thanks for your rate :)';
// ONLY FOR THE DEMO, YOU CAN REMOVE THE CODE UNDER
$aResponse['server'] = '<strong>Success answer :</strong> Success : Your rate has been recorded. Thanks for your rate :)<br />';
$aResponse['server'] .= '<strong>Rate received :</strong> '.$rate.'<br />';
$aResponse['server'] .= '<strong>ID to update :</strong> '.$id;
// END ONLY FOR DEMO
echo json_encode($aResponse);
}
else
{
$aResponse['error'] = true;
$aResponse['message'] = 'An error occured during the request. Please retry';
// ONLY FOR THE DEMO, YOU CAN REMOVE THE CODE UNDER
$aResponse['server'] = '<strong>ERROR :</strong> Your error if the request crash !';
// END ONLY FOR DEMO
echo json_encode($aResponse);
}
}
else
{
$aResponse['error'] = true;
$aResponse['message'] = '"action" post data not equal to \'rating\'';
// ONLY FOR THE DEMO, YOU CAN REMOVE THE CODE UNDER
$aResponse['server'] = '<strong>ERROR :</strong> "action" post data not equal to \'rating\'';
// END ONLY FOR DEMO
echo json_encode($aResponse);
}
}
else
{
$aResponse['error'] = true;
$aResponse['message'] = '$_POST[\'action\'] not found';
// ONLY FOR THE DEMO, YOU CAN REMOVE THE CODE UNDER
$aResponse['server'] = '<strong>ERROR :</strong> $_POST[\'action\'] not found';
// END ONLY FOR DEMO
echo json_encode($aResponse);
}
ojala me puedan ayudar gracias de ante mano