Ante todo gracias por el interes, a ver, he probado esto:
Código PHP:
<?PHP
$user_name = "x";
$password = "x";
$database = "x";
$server = "localhost:/tmp/mysql5.sock";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$SQL = "SELECT tmo4c_users.name, COUNT (idUsuario) FROM tmo4c_users, tmo4c_zst_reservas WHERE tmo4c_users.id = tmo4c_zst_reservas.idUsuario GROUP BY tmo4c_zst_reservas.idUsuario ORDER BY idUsuario desc";
$resultado = mysql_query($SQL, $db_handle);
while($row = mysql_fetch_array($resultado)){
echo $row[0];
echo $row[1];
}
}
else {
print "Database NOT Found ";
mysql_close($db_handle);
}
?>
Sigo atascado...
Falla en el while Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource i
Saludos