He modificado el script y lo tengo de la siguiente manera:
Código PHP:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Gallery - Image Upload</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" href="styles.css"/>
<script language="JavaScript">
//MultiPowUpload_onComplete. Invoked when the upload or download of single file operation has successfully completed
function MultiPowUpload_onComplete(type, index, serverResponse)
{
addThumbnail(serverResponse);
//acá modificamos:
window.contenido=document.getElementById('thumbnails');
[COLOR="Red"]// Se crea un nuevo "INPUT"
var newInput = document.createElement('image');
newInput.type = 'hidden';
newInput.name = 'myImage[]';
newInput.value = window.contenido;
//alert(newInput.value);
document.forms[0].submit();[/COLOR]
}
function addThumbnail(source)
{
var Img = document.createElement("img");
Img.style.margin = "5px";
if(source != "no_image")
Img.src = source;
else
Img.src = "Images/elementitlogo.gif";
document.getElementById("thumbnails").appendChild(Img);
//document.getElementById("thumbnails").innerHTML += "<a href=\"javascript:alert('Portada de Album')\"><img src=\"icon_photoalbum.gif\" border=\"0\"/></a>";
}
</script>
</head>
<body>
<h3>Image Upload Area</h3>
<p> </p>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td><form name="upload" action="image_upload.php" method="post">
<p> </p>
<table width="32%" border="0" align="left" cellpadding="5" cellspacing="0">
<tr>
<td>Photo Album:</td>
<td><select name="albums" id="albums">
<?php
include("include/config.php");
db_connect();
mysql_query("SET NAMES 'utf8'");
header('Content-Type: text/html; charset=utf-8' );
$sql = "SELECT album_id, album_name FROM album";
$result = @mysql_query( $sql ) or die("Error retrieving records: " . mysql_error());
while ( $row = mysql_fetch_array($result) ){
echo("<option value=" . $row['album_id'] . ">" . $row['album_name'] . "</option>");
}
?>
</select>
</td>
</tr>
<tr>
<td align="left" colspan="2">
<div id="MultiPowUpload_holder">You need at least 9 version of Flash player. Download last version
<a target="_blank" href="http://www.adobe.com/shockwave/download/alternates/">here</a>!
</div>
<!-- SWFObject home page: http://code.google.com/p/swfobject/ -->
<script type="text/javascript" src="swfobject.js"></script>
<script type="text/javascript">
var params = {
BGColor: "#F8F6E6"
};
var attributes = {
id: "MultiPowUpload",
name: "MultiPowUpload"
};
var flashvars = {
//uploadUrl: "FileProcessingScripts/PHP/createthumbnail.php",
uploadUrl: "createthumbnail.php",
useExternalInterface: "Yes",
fileTypes: "JPEG images|*.jpg\;*.jpeg"
};
swfobject.embedSWF("ElementITMultiPowUpload2.swf", "MultiPowUpload_holder", "450", "350", "9.0.0", "expressInstall.swf", flashvars, params, attributes);
</script>
</td>
</tr>
<tr>
<td></td>
<td><!-- <input name="submit" type="submit" id="submit" value="Continue" /> --></td>
</tr>
<!-- <div id="thumbnails"></div> -->
</table>
<p/>
</form>
</td>
</tr>
</table>
<p/>
<table>
<tr>
<td colspan="2">
<table width="*" border="0" align="left" cellpadding="3" cellspacing="0" class="bottommenu">
<tr>
<td class="bottommenu"><a href="index.php">Main Menu</a> | <a href="new_album.php">Create
New Album</a> | <a href="gallery.php">View Gallery</a></td>
</tr>
</table>
</td>
</tr>
</table>
</body>
</html>
El código que está en rojo lo he añadido para que el formulario se envíe automáticamente y no lo hace.
Qué estoy haciendo mal?
24/12/2008, 13:48
Cómo hacer para capturar el contenido del div en una variable 
