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aspsmartupload

Estas en el tema de aspsmartupload en el foro de ASP Clásico en Foros del Web. Hola: El problema que tengo es que cuando subo algunos ficheros usando aspsmartupload me funciona bien pero cuando subo un otros se me demora demasiado ...
  #1 (permalink)  
Antiguo 13/12/2002, 07:40
 
Fecha de Ingreso: noviembre-2002
Mensajes: 54
Antigüedad: 21 años, 7 meses
Puntos: 0
aspsmartupload

Hola:

El problema que tengo es que cuando subo algunos ficheros usando aspsmartupload me funciona bien pero cuando subo un otros se me demora demasiado y termina por no encontrar el script que ejecuta el upload.
Mi codigo usa un formulario multipart/form-data con el action="Upload.asp" donde Upload.asp define las variables del aspsmart... y ejecuta los metodos upload y save. Pero como dije antes trato de subir algunos ficheros y no funciona
Gracias
  #2 (permalink)  
Antiguo 15/12/2002, 15:35
Avatar de Torus  
Fecha de Ingreso: enero-2002
Ubicación: Tú buscame y me encontraras
Mensajes: 413
Antigüedad: 22 años, 5 meses
Puntos: 0
Espero que te sirva ojo va en dos partes

<%response.buffer=true
Func = Request("Func")

if isempty(Func) Then
Func = 1
End if

Select Case Func
Case 1
'You do not need to use this form to
'send your files.
BrowseServer = Request.Form("BrowseServer")

%>
<H2>File Upload Form.</H2>

<TABLE>


<FORM ENCTYPE="multipart/form-data" ACTION="saveany.asp?func=2" METHOD=POST id=form1 name=form1>
<TR><TD><strong>Debug Options.</strong><BR></TD></TR>
<TR><TD><INPUT NAME=Options TYPE=CheckBox Value='Raw'>Create Raw File<BR></TD></TR>
<TR><TD><INPUT NAME=Options TYPE=CheckBox Value='Boundry'>Create Boundry File<BR><br></TD></TR>

<TR><TD><strong>Hit the [Browse Server] button to find the folder on the server to upload to.</strong><BR></TD></TR>
<TR><TD><INPUT NAME=ServerPath SIZE=30 TYPE=Text value='<%= BrowseServer %>'><Input type=button value="Browse Server" onclick="document.location='saveany.asp?func=3'" id=button1 name=button1><BR><br></TD></TR>

<TR><TD><strong>Hit the [Browse] button to find the file on your computer.</strong><BR></TD></TR>
<TR><TD><INPUT NAME=File1 SIZE=30 TYPE=file><BR></TD></TR>
<TR><TD><INPUT NAME=File2 SIZE=30 TYPE=file><BR></TD></TR>
<TR><TD><INPUT NAME=File3 SIZE=30 TYPE=file><BR><br></TD></TR>
<TR><TD><strong>Enter security password.</strong><BR></TD></TR>
<TR><TD><INPUT NAME=Password SIZE=30 TYPE=Text><BR></TD></TR>
<TR><TD align=left><INPUT name=submit type="submit" value="Upload File"><BR><BR></TD></TR>
<TR><TD>NOTE: Please be patient, you will not receive any notification until the file is completely transferred.<BR><BR></TD></TR>
</form>
</TABLE>
<%
Case 2

Server.ScriptTimeout=300
ForWriting = 2

adLongVarChar = 201
lngNumberUploaded = 0

'Get binary data from form
noBytes = Request.TotalBytes
binData = Request.BinaryRead (noBytes)

'convery the binary data to a string
Set RST = CreateObject("ADODB.Recordset")
LenBinary = LenB(binData)

if LenBinary > 0 Then
RST.Fields.Append "myBinary", adLongVarChar, LenBinary
RST.Open
RST.AddNew
RST("myBinary").AppendChunk BinData
RST.Update
strDataWhole = RST("myBinary")
End if


'get the boundry indicator
strBoundry = Request.ServerVariables ("HTTP_CONTENT_TYPE")
lngBoundryPos = instr(1,strBoundry,"boundary=") + 8
strBoundry = "--" & right(strBoundry,len(strBoundry)-lngBoundryPos)

'ParseForm returns a dictionary object
'You can ParseForm any time after the
'Boundry indicator is set.

set dPassword = ParseForm("Password")
set dOptions = ParseForm("Options")

'both of these are valid
Response.Write ParseForm("Password").item(0) & "<br>"
Response.write dPassword.item(0) & "<br>"

SavePath = ParseForm("ServerPath").item(0)
if SavePath = "" or isempty(SavePath) then
Response.Write "<H2> The following Error occured.</H2>"
Response.Write "You did not enter a server path to save your file to."
Response.Write "<BR><BR>Hit the back button, make the needed corrections and resubmit your information."
Response.Write "<BR><BR><INPUT type='button' onclick='history.go(-1)' value='<< Back' id='button'1 name='button'1>"
Response.End
end if

intCount = dOptions.count

if intCount > 0 then
for x = 0 to intCount
Select case dOptions.item(x)
case "Raw"
Raw = True
case "Boundry"
Boundry = True
end select
next
else
Raw = false
Boundry = false
end if
if dPassword.item(0) <> "oktosend" then
Response.Write "<H2> The following Error occured.</H2>"
Response.Write "The Password you entered is invalid."
Response.Write "<BR><BR>Hit the back button, make the needed corrections and resubmit your information."
Response.Write "<BR><BR><INPUT type='button' onclick='history.go(-1)' value='<< Back' id='button'1 name='button'1>"
Response.End
end if
'Creates a raw data file for with all
'data sent. Uncomment for debuging.
if Raw then
Set fso = CreateObject("Scripting.FileSystemObject")
Set f = fso.OpenTextFile(SavePath & "\raw.txt", ForWriting, True)
f.Write strDataWhole
set f = nothing
set fso = nothing
end if


'Get first file boundry positions.
lngCurrentBegin = instr(1,strDataWhole,strBoundry)
lngCurrentEnd = instr(lngCurrentBegin + 1,strDataWhole,strBoundry) - 1



countloop = 0

Do While lngCurrentEnd > 0

'Get the data between current boundry
'and remove it from the whole.
strData = mid(strDataWhole,lngCurrentBegin, (lngCurrentEnd - lngCurrentBegin) + 1)

'Remove the file data from the whole
'strDataWhole = replace(strDataWhole,strData,"")


'Get the full path of the current file.
lngBeginFileName = instr(1,strdata,"filename=") + 10
lngEndFileName = instr(lngBeginFileName,strData,chr(34))
'Make sure they selected at least one
'file.
if lngBeginFileName = lngEndFileName and lngNumberUploaded = 0 Then

Response.Write "<H2> The following Error occured.</H2>"
Response.Write "You must Select at least one file To upload"
Response.Write "<BR><BR>Hit the back button, make the needed corrections and resubmit your information."
response.Write "<BR><BR><INPUT type='button' onclick='history.go(-1)' value='<< Back' id='button'1 name='button'1>"
Response.End
End if
'There could be one or more empty file b
'
'oxes.
if lngBeginFileName <> lngEndFileName and lngBeginFileName - 10 <> 0 Then
strFilename = mid(strData,lngBeginFileName,lngEndFileName - lngBeginFileName)

'Creates a raw data file with data
'between current boundrys. Uncomment
'for debuging.

if Boundry then
Set fso = CreateObject("Scripting.FileSystemObject")
Set f = fso.OpenTextFile(SavePath & "\raw_" & lngNumberUploaded & ".txt", ForWriting, True)
f.Write strData
set f = nothing
set fso = nothing
end if

'Loose the path information and keep
'just the file name.
tmpLng = instr(1,strFilename,"\")
Do While tmpLng > 0
PrevPos = tmpLng
tmpLng = instr(PrevPos + 1,strFilename,"\")
Loop

FileName = right(strFilename,len(strFileName) - PrevPos)

'Get the begining position of the file
'data sent.
'if the file type is registered with
'the browser then there will be a
'Content-Type
lngCT = instr(1,strData,"Content-Type:")

if lngCT > 0 Then
lngBeginPos = instr(lngCT,strData,chr(13) & chr(10)) + 4
Else
lngBeginPos = lngEndFileName
End if
'Get the ending position of the file
'data sent.
lngEndPos = len(strData)

'Calculate the file size.
lngDataLenth = (lngEndPos - lngBeginPos) -1
'Get the file data
strFileData = mid(strData,lngBeginPos,lngDataLenth)
'Create the file.
Set fso = CreateObject("Scripting.FileSystemObject")
Set f = fso.OpenTextFile(SavePath & "\" & FileName, ForWriting, True)
f.Write strFileData
Set f = nothing
Set fso = nothing

if lngNumberUploaded = 0 then
Response.Write "<Strong>Saving Files...</strong><br><br>"
end if

Response.Write SavePath & "\" & FileName & "<br>"

lngNumberUploaded = lngNumberUploaded + 1

End if

'Get then next boundry postitions if
'any.
lngCurrentBegin = lngCurrentEnd
lngCurrentEnd = instr(lngCurrentBegin + 9 ,strDataWhole,strBoundry) - 1

'Prevents infinate loop.
countloop = countloop + 1
if countloop = 100 then
Response.Write "looped 100 times terminating script!"
Response.End
end if
loop

Response.Write "<strong>" & lngNumberUploaded & " File(s) Uploaded</strong>"
Response.Write "<BR><BR><INPUT type='button' onclick='document.location=" & chr(34) & "saveany.asp" & chr(34) & "' value='<< Back to Listings' id='button'1 name='button'1>"
Case 3

'get prev path if any
path = Request.QueryString("Path")
'if not assign one
if path = "" or isempty(path) then
path = "c:\inetpub"
end if
'create filesystemobject
Set fso = CreateObject("Scripting.FileSystemObject")
'get a folder object
set f = fso.GetFolder(path)
path = f.path

'limit access to hard drive
if lcase(left(path,10)) <> "c:\inetpub" then
path = "C:\Inetpub"
set f = fso.GetFolder(path)
path = f.path
end if

Response.Write "<H2>Server Browse
__________________
Hay tanto que aprender y tan poco tiempo
  #3 (permalink)  
Antiguo 15/12/2002, 15:36
Avatar de Torus  
Fecha de Ingreso: enero-2002
Ubicación: Tú buscame y me encontraras
Mensajes: 413
Antigüedad: 22 años, 5 meses
Puntos: 0
Form.</H2>"
Response.Write "<FORM ACTION='saveany.asp?func=1' METHOD=POST>"
Response.Write "<table width=400 border=1 cellpadding=0 cellspacing=1>" & vbcrlf
Response.Write "<tr><th colspan=2>" & path & "</th></tr>"
Response.Write "<tr><td colspan=2 align=left><a href='saveany.asp?func=3&path=" & path & "\..'><strong>Parent ..</strong></a></td></tr>" & vbcrlf

'get subfolders collection
set fc = f.subfolders

'enum subfolders
for each folder in fc
Response.Write "<tr><td align=left><INPUT NAME=BrowseServer TYPE=CheckBox Value='" & folder.path & "'></td><td style='padding-left: 20px;' align=left><a href='saveany.asp?func=3&path=" & folder.path & "'>" & folder.name & "</a></td></tr>" & vbcrlf
next

'if there is a folder display the select folder button
if fc.count > 0 then
Response.Write "<TR><TD align=left colspan=2><br><INPUT name=submit type='submit' value='Select Folder'></TD></TR>"
end if

Response.Write"<tr><td colspan=2><INPUT name=cancel type='Button' value='Cancel' onclick=document.location='saveany.asp?func=1'></td></tr>"

Response.Write "</table>" & vbcrlf
Response.Write "</form>"
end select

%>
</BODY>
</HTML>


<SCRIPT LANGUAGE=vbscript RUNAT=Server>
Function ParseForm(strFieldName)

Set strFormData = CreateObject("Scripting.Dictionary")
lngCount = -1
'Try to find the Field
lngNamePos = instr(1,strDataWhole,"name=" & chr(34) & strFieldName & chr(34))

'Parse through data in search of fields
do while lngNamePos <> 0
lngCount = lngCount + 1
lngBeginFieldData = instr(lngNamePos,strDataWhole,vbcrlf & vbcrlf)+4
lngEndFieldData = instr(lngBeginFieldData,strDataWhole,vbcrlf)
strFormData.Add lngCount, mid(strDataWhole,lngBeginFieldData,lngEndFieldData-lngBeginFieldData)
lngNamePos = instr(lngEndFieldData,strDataWhole,"name=" & chr(34) & strFieldName & chr(34))

loop
set ParseForm = strFormData
end function
</SCRIPT>
__________________
Hay tanto que aprender y tan poco tiempo
  #4 (permalink)  
Antiguo 15/12/2002, 17:39
Avatar de maestro  
Fecha de Ingreso: febrero-2002
Ubicación: España
Mensajes: 2.364
Antigüedad: 22 años, 4 meses
Puntos: 1
Joe..... Torus, ¿hacia falta todo ese rollo para explicar las 4 lineas de codigo que usa aspsmartupload?

Formulario HTM (upload.htm) donde seleccionamos las imagenes, he colocado 3 inputs para poder enviar de 3 en tres si queremos:
<FORM method="POST" ENCTYPE="multipart/form-data" ACTION="upload.asp">
<INPUT TYPE="FILE" NAME="fichero"><br>
<INPUT TYPE="FILE" NAME="fichero1"><br>
<INPUT TYPE="FILE" NAME="fichero2"><br>
INPUT TYPE="submit" value="Enviar Fichero/s">
</FORM>



Pagina ASP (upload.asp) donde recibimos los datos del formulario:
<%
On Error Resume Next
Dim myUpload
Dim intCount
Set myUpload = Server.CreateObject("aspSmartUpload.SmartUpload")
myUpload.AllowedFilesList="jpg,gif,bmp,jpeg,tga,pc x,png"
' Esto hace que solo puedas enviar esa extensiones
myUpload.DenyPhysicalPath=True
myUpload.Upload
intCount = myUpload.Save("upload")
If Err Then
Response.Write("&nbspNo se puede enviar el fichero(s) seleccionados.<br>")
Response.Write("&nbsp<font color=RED><b>Seleccion no valida : </b>" & Err.description)
else
Response.Write(intCount & " <b>fichero(s) enviado.</b>")
end if
%>
__________________
Jose Maria Fernandez
[email protected]
Http://www.expansionweb.net
  #5 (permalink)  
Antiguo 16/12/2002, 07:18
 
Fecha de Ingreso: noviembre-2002
Mensajes: 54
Antigüedad: 21 años, 7 meses
Puntos: 0
Hola y les agradezco mucho su amabilidad, pero estuve haciendo la siguiente prueba para ver donde estaba el problema.

Elimine todo el codigo del aspsmartupload en el script "upload.asp" y solo deje que se imprimiera un texto y en algunos momentos me daba el error o sea que persistia el problema. Cuando unico me mostraba el texto que deje en "upload.asp" era cuando le quitaba al formulario multipart/form-data. Da la impresion que depende de la velocidad de coneccion al algo similar.

Alguien puede explicarme esto
Atención: Estás leyendo un tema que no tiene actividad desde hace más de 6 MESES, te recomendamos abrir un Nuevo tema en lugar de responder al actual.
Respuesta




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